By Paul Withers | 11/7/22 4:28 AM | Development - Notes / Domino | Added by Roberto Boccadoro
Look at the following code and guess the error message.
Public firstName as String
Dim p as New Person
Sub outerPrint(msg as Variant)
Sub innerPrint(msg as Variant)
If (TypeName(msg) = "PERSON") Then
The error message received will be a Type Mismatch, on the line innerPrint(msg). But the cause might be harder to work out - although the title of this blog post might point you in the direction.